001
002
003
004
005
006
007
008
009
010
011
012
013
014
015
016
017
018
019
020
021
022
023
024
025
026
027
028
029
030
031
032
033
034
035
036
037
038
039
040
041
042
043
044
045
046
047
048
049
050
051
052
053
054
055
056
057
058
059
060
061
062
063
064
065
066
067
068
069
070
071
072
073
074
075
076
077
078
079
080
081
082
083
084
085
086
087
088
089
090
091
092
093
094
095
096
097
098
099
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
package algs63;
import  stdlib.*;

/* ***********************************************************************
 *  Compilation:  javac SuffixArray.java
 *  Execution:    java SuffixArray < input.txt
 *
 *  A data type that computes the suffix array of a string.
 *
 *  % java SuffixArray < abra.txt
 *    i ind lcp rnk  select
 *  ---------------------------
 *    0  11   -   0  !
 *    1  10   0   1  A!
 *    2   7   1   2  ABRA!
 *    3   0   4   3  ABRACADABRA!
 *    4   3   1   4  ACADABRA!
 *    5   5   1   5  ADABRA!
 *    6   8   0   6  BRA!
 *    7   1   3   7  BRACADABRA!
 *    8   4   0   8  CADABRA!
 *    9   6   0   9  DABRA!
 *   10   9   0  10  RA!
 *   11   2   2  11  RACADABRA!
 *
 *  WARNING: This program assumes that the {@code substring()} method takes
 *  constant time and space. Beginning with Oracle / OpenJDK Java 7, Update 6,
 *  the substring method takes linear time and space in the size of the
 *  extracted substring. Do NOT use this code with such versions.
 *
 *  See <a href = "http://java-performance.info/changes-to-string-java-1-7-0_06/">this article</a>
 *  for more details.
 *
 *************************************************************************/

import java.util.Arrays;

public class SuffixArray {
  private final String[] suffixes;
  private final int N;

  public SuffixArray(String s) {
    N = s.length();
    suffixes = new String[N];
    for (int i = 0; i < N; i++)
      suffixes[i] = s.substring(i);
    Arrays.sort(suffixes);
  }

  // size of string
  public int length() { return N; }

  // index of ith sorted suffix
  public int index(int i) { return N - suffixes[i].length(); }

  // ith sorted suffix
  public String select(int i) { return suffixes[i]; }

  // number of suffixes strictly less than query
  public int rank(String query) {
    int lo = 0, hi = N - 1;
    while (lo <= hi) {
      int mid = lo + (hi - lo) / 2;
      int cmp = query.compareTo(suffixes[mid]);
      if      (cmp < 0) hi = mid - 1;
      else if (cmp > 0) lo = mid + 1;
      else return mid;
    }
    return lo;
  }

  // length of longest common prefix of s and t
  private static int lcp(String s, String t) {
    int N = Math.min(s.length(), t.length());
    for (int i = 0; i < N; i++)
      if (s.charAt(i) != t.charAt(i)) return i;
    return N;
  }

  // longest common prefix of suffixes(i) and suffixes(i-1)
  public int lcp(int i) {
    return lcp(suffixes[i], suffixes[i-1]);
  }

  // longest common prefix of suffixes(i) and suffixes(j)
  public int lcp(int i, int j) {
    return lcp(suffixes[i], suffixes[j]);
  }

  public static void main(String[] args) {
    String s = StdIn.readAll().replaceAll("\n", " ").trim();
    SuffixArray suffix = new SuffixArray(s);


    StdOut.println("  i ind lcp rnk  select");
    StdOut.println("---------------------------");

    for (int i = 0; i < s.length(); i++) {
      int index = suffix.index(i);
      String ith = "\"" + s.substring(index, Math.min(index + 50, s.length())) + "\"";
      // String ith = suffix.select(i);
      int rank = suffix.rank(ith);
      if (i == 0) {
        StdOut.format("%3d %3d %3s %3d  %s\n", i, index, "-", rank, ith);
      }
      else {
        int lcp = suffix.lcp(i, i-1);
        StdOut.format("%3d %3d %3d %3d  %s\n", i, index, lcp, rank, ith);
      }
    }

  }

}