CSC300: Homework [1/2] |

+ Read Algorithms through the end of 2.5 (including 2.2,2.3) You should pay closer attention to 2.2 than 2.3 since mergesort will be on the final exam, but quicksort will not. + Do these problems on paper, but don't hand them in: Be sure to do the starred ones. 2.4.2 (Don't confuse find-the-max and remove-the-max) 2.4.4 2.4.5 2.4.9* (Draw min heaps.) 2.4.11 (Also say why. Don't confuse find-the-max and remove-the-max) 2.4.12 (Also say why. Don't confuse find-the-max and remove-the-max) 2.4.15* (The method MinPQ.isMinHeap does this recursively. What would an iterative solution be? You should make sure you understand this and can do it without looking at MinPQ.isMinHeap.) 2.4.27* (Argue that your solution is constant time/space.) + Do the MyDeckSort assignment and hand in MyDeckSort.java Your goal is to implement the sort(MyDeck) method of MyDeckSort. You can use only the public method of MyDeck. You should not change the functionality of MyDeck. Hand in only MyDeckSort.java This is based on problem 2.1.14 from the text. To get started, download the zip file from d2l. Unzip and put MyDeck and MyDeckSort in algs21 package. You need only edit MyDeckSort. The Deck class has the following API: MyDeck (int N) // create a randomized Deck of size N int size () // return the size of N int ops () // return the number of operations performed on this Deck boolean topGreaterThanNext () // compare top two items void swapTopTwo () // swap top two itens void moveTopToBottom () // move top item to bottom void isSorted () // check if isSorted (throws exception if not) -------------------- MyDeckSort Hints: Assume that the deck d has d.size() cards. So you might say: for (int i=0; i<d.size(); i++) { if (d.topGreaterThanNext()) { d.swapTopTwo () } d.moveTopToBottom () } Note that you can go through the whole deck using a loop: for (int i=0; i<d.size(); i++) { ... d.moveTopToBottom () } You can also go through the deck d.size() times! for (int i=0; i<d.size(); i++) { for (int j=0; j<d.size(); j++) { ... d.moveTopToBottom () } } You can do different things at different point of the process! for (int i=0; i<d.size(); i++) { for (int j=0; j<i; j++) { ... d.moveTopToBottom () } for (int j=i; j<d.size(); j++) { ... d.moveTopToBottom () } }